I've made some super cool custom blocks!

I've made a program with five custom made blocks, some of them I've seen many people asking for! Here's what they look like:
Collection of cool new blocks script pic (5)
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Here's the link to the project: Collection of cool new blocks!

These blocks are cool..

do you think you could make a do ... while loop? they first execute what's inside, then check if it should continue repeating itself

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your contains block is brokenuntitled script pic (1)
oh nvm i thought it was the scratch contains block not contains a letter

I think the repeat...while block in the library does that

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Hey, I could make a block like that if you wanted.

I've made the block you've requested!
Collection of cool new blocks! script pic (2)

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The 'repeat forever after' block is broken now, you see the 'unevaluated boolean' option means that instead of a true/false value, it will report a block.
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It will never equal true, unless it's evaluated using image. You need to use image, so that it will evaluate the block every time.

One thing with the 'mouse on screen?' boolean:

The stage is resizable, so if a user changes the stage size the boolean will be inaccurate.

See if you could try make it adjust with the stage size, (this could be hard or impossible to do.)

Nah, not hard.
U2L3-WordPuzzleSolver script pic
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The "Strings, Multi-line input" library has the block you're looking for:
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I am really suprised. It is like you know every single ...Thing about snap?...nah

Nice collection. One little thing about programming style: You have


You can skip the IF and just do

Cool that that works, no?

I'm assuming he does, considering he the one who MADE it.

That is really cool!

I was thinking, if anyone has a block they want to see, I could attempt to make it.

Cool, but the VALUE OF DIGIT OF block I have suggested, and it is supposed to report the digit from the right, not the left.

Sure, I can change that.

if you can, cool! I have been trying to do that and it is hard for me.

Yeah, I'm coding it right now, and it is pretty hard. But I think I have an equation to get the correct item. It's digit_num - (length(num) - 1).