Around 30 Custom blocks

No, I was talking about 80=ff/2.

Also, how do you do latex here?

$$ \LaTeX $$

$$80= {ff}/{2}$$

Is that good?

Then why not use $$7F +(1/A)$$??

No, A is 10 in hexadecimal! And you could probably try something to allow that.

No, 10 in decimal is A in hexadecimal!!! THAT'S what I want!

:weary: I wasn't trying to argue.

Well, you thought I was talking about 10 (hexadecimal) but I was talking about 10 (decimal).

Oh. I see. I calculated it wrong. (Oh, btw, You can denote a base like this: 146)

Oh. Also HOW DO YOU DO THAT!?

14<sub>6</sub>
146

Oh, thanks. So essentially you thought I meant (1016 = 1610) when I meant (1010 = A16)

Yeah.

So is there a way to fit ($$7F +1/A$$)16?

Unfortunately, no.

:frowning:
:-(.

stop complaining about the color. im just wondering how he got 2731 digits of pi.

wym

There are plenty of infinite Σs that can generate digits of π.

Like this one?